Linearising equations question

I'm slightly stuck on these two questions, anyone got any hints?

1) I recommend remembering the equation of a straight line which is y = mx+ c, where m is the gradient and c is the y intercept. It may also help if you see it as Ek = -Wsin(θ) s + E0.

In this case substitute the value for W in: Ek = -2.39 sin(θ) s + E.

Then set -2.39 sin(θ) = -0.98 as we can see that -Wsin(θ) is the gradient and we are given the value of the gradient. Remember it is -2.39 not 2.39 as it is -W.

This equation can be very simply solved (I hope!): -2.39 sin(θ) = -0.98 (solve for θ)

2) Again remember the equation of a straight line and we can see that the gradient which in this case is (e/h) = 2.41x10^14 and we know the value of e. It should be quite easy to find the value of h.

And the same can be done for the intercept to find the other value.

wouldn't the first one have to be rearranged so that the s is the denominator and Ek the numerator and then substitute -0.98?

(Original post by Zain-)

Thanks! I did like 90% of that but I got stuck because I thought there were two unknowns, one being theta (sorry on a phone rn) I knew what the gradient was and did equate the whole thing to -0.98 but just couldn't figure the whole thing out because I thought 0.98= E0 -2.39 sin(theta) BUT we don't know what E0 is as well as sin(theta) so I was completely stumped.
Are you saying that E0 is somehow not part of the gradient?




Idts, the x and y values were in the right order so you dont need to rearrange further (for the first one anyways) s = x and Ek = y which means the things in the middle is the gradient