# Help Pls

Watch
Announcements
#1
Anyone know how to do the following question? Thanks.

0
1 week ago
#2
Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you integrate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.

For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you integrate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Last edited by awc14; 1 week ago
1
1 week ago
#3
(Original post by awc14)
Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you differentiate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.

For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you differentiate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

^^^ This, but integrate rather than differentiate.
1
1 week ago
#4
(Original post by mqb2766)
^^^ This, but integrate rather than differentiate.
Thank you, how stupid of me
0
#5
(Original post by awc14)
Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you integrate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.

For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you integrate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

hello,
I got 76.6m for part a. Is that right?
For part b, I'm not sure what to sub in (t=?) to find C in the second equation.
0
1 week ago
#6
(Original post by josefgas5)
hello,
I got 76.6m for part a. Is that right?
For part b, I'm not sure what to sub in (t=?) to find C in the second equation.
a) looks good
https://www.wolframalpha.com/input/?...29+from+0+to+5

b) when t=5, the curves must join so s=76.6. which gives C
0
#7
(Original post by mqb2766)
a) looks good
https://www.wolframalpha.com/input/?...29+from+0+to+5

b) when t=5, the curves must join so s=76.6. which gives C
I got 109.9m for the final displacement. Can anyone confirm if its correct or not? Thanks
0
1 week ago
#8
(Original post by josefgas5)
I got 109.9m for the final displacement. Can anyone confirm if its correct or not? Thanks
https://www.wolframalpha.com/input/?...E2+from+5+to+6
You can use "learn" to use it, it is quite simple and useful.
You obviously add C to that.
0
#9
(Original post by mqb2766)
https://www.wolframalpha.com/input/?...E2+from+5+to+6
You can use "learn" to use it, it is quite simple and useful.
You obviously add C to that.
Thank you!!
0
X

new posts Back
to top
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### Poll

Join the discussion

Yes, and I've sent off my application! (193)
54.99%
I've made my choices but havent sent my application yet (49)
13.96%
I've got a good idea about the choices I want to make (40)
11.4%
I'm researching but still not sure which universities I want to apply to (33)
9.4%
I haven't started researching yet (21)
5.98%
Something else (let us know in the thread!) (15)
4.27%