josefgas5
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Anyone know how to do the following question? Thanks.

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awc14
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Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you integrate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.


For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you integrate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Hope this made sense!
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mqb2766
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(Original post by awc14)
Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you differentiate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.


For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you differentiate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Hope this made sense!
^^^ This, but integrate rather than differentiate.
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awc14
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(Original post by mqb2766)
^^^ This, but integrate rather than differentiate.
Thank you, how stupid of me
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josefgas5
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(Original post by awc14)
Hello,

For part a you have the equation for the velocity of the particle when t = 5. If you integrate this in terms of t you have the equation for the displacement of the particle, so just plug t = 5 into this.


For part b, you want to work out the displacement of the particle in the next second. You need to use the second equation for this, as the first is not true for t > 5. If you integrate this equation, then plug in t = 1 you have worked out the displacement of the particle in the next second. Add your answer from part a to this and you have worked out the total displacement from 0 to 6s.

Hope this made sense!
hello,
I got 76.6m for part a. Is that right?
For part b, I'm not sure what to sub in (t=?) to find C in the second equation.
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mqb2766
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(Original post by josefgas5)
hello,
I got 76.6m for part a. Is that right?
For part b, I'm not sure what to sub in (t=?) to find C in the second equation.
a) looks good
https://www.wolframalpha.com/input/?...29+from+0+to+5

b) when t=5, the curves must join so s=76.6. which gives C
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josefgas5
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(Original post by mqb2766)
a) looks good
https://www.wolframalpha.com/input/?...29+from+0+to+5

b) when t=5, the curves must join so s=76.6. which gives C
I got 109.9m for the final displacement. Can anyone confirm if its correct or not? Thanks
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mqb2766
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(Original post by josefgas5)
I got 109.9m for the final displacement. Can anyone confirm if its correct or not? Thanks
https://www.wolframalpha.com/input/?...E2+from+5+to+6
You can use "learn" to use it, it is quite simple and useful.
You obviously add C to that.
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josefgas5
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(Original post by mqb2766)
https://www.wolframalpha.com/input/?...E2+from+5+to+6
You can use "learn" to use it, it is quite simple and useful.
You obviously add C to that.
Thank you!!
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