papie
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papie
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I had 1/2 for a and pi/4 for b. I am a bit struggling with these newly added Transformations for AS mathematics. I know the graph of tan x, but from there I don't know what transformations do i apply to get to that graph.
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mqb2766
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(Original post by papie)
I had 1/2 for a and pi/4 for b. I am a bit struggling with these newly added Transformations for AS mathematics. I know the graph of tan x, but from there I don't know what transformations do i apply to get to that graph.
If you know b, you can identify the "origin" (0,0) for tan(0) and identify the vertical offset c.
Then you could use the tan(pi/4)=1 to get the vertical scaling a.

Agree with b=pi/4. What do you think for c at x=pi/4 so tan(pi/4-pi/4) = tan(0) = ... Write down the points and the equations clearly if necessary.
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