lala5646
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#1
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#1
express 3x^2-18x+16 in the form a(x-b)^2+c

no idea!
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Muttley79
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#2
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#2
(Original post by lala5646)
express 3x^2-18x+16 in the form a(x-b)^2+c

no idea!
Completed square form - are you studying GCSE?

If you haven't learned this then expand out the brackets and compare coefficients - post your working
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lala5646
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#3
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#3
(Original post by Muttley79)
Completed square form - are you studying GCSE?

If you haven't learned this then expand out the brackets and compare coefficients - post your working
so would it be 3(x^2-18x)+16
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Muttley79
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#4
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#4
(Original post by lala5646)
so would it be 3(x^2-18x)+16
No - that's not the same -- if you are going to do it like this you need to take out a factor of 3 from 18 too

a(x-b)^2+c = what when expanded?
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lala5646
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#5
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#5
(Original post by Muttley79)
No - that's not the same -- if you are going to do it like this you need to take out a factor of 3 from 18 too

a(x-b)^2+c = what when expanded?
ah so would it be 3x(x - 6)+16
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MayaVellichor
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#6
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#6
Start by just taking out the 3 from x^2-18x
So it is 3(x^2-6x)+16
Then complete the square
Last edited by MayaVellichor; 1 month ago
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lala5646
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#7
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#7
how do u do that pls
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Muttley79
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#8
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#8
(Original post by lala5646)
ah so would it be 3x(x - 6)+16
Just take out the factor of 3 - you need the other terms
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lala5646
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#9
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#9
i dont get it
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MayaVellichor
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#10
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#10
Name:  16349983424031546764515176623874.jpg
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This should explain the method
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lala5646
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#11
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#11
so would it be 3(x^2 - 2x) + 9
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ukii
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#12
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#12
Here's my solution.
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Sm 002 u mug
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#13
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#13
(Original post by lala5646)
so would it be 3(x^2 - 2x) + 9
Not quite,
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MayaVellichor
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#14
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lala5646
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#15
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#15
love u all
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