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CaCO3 + H2O2 CaO2.xH2O + CO2 + H2O

Since excess hydrogen peroxide was present, the theoretical yield is based on the quantity of calcium carbonate used in the synthesis.

RMM of calcium carbonate = 72 g mol-1
Calcium carbonate used = 10.6 g Moles calcium carbonate used = 0.14623 mol [4 marks]

The number of moles of CaCO3 used is called the REACTION SCALE. How many moles of calcium peroxide hydrate will be produced from this number of moles of CaCO3 assuming that the reaction goes to completion (i.e. giving 100% of product or the ‘theoretical yield’)? Show your reasoning/calculation. [4 marks]




From your analytical results, the value of x will now be known. Using this value, (a) calculate the RMM of calcium peroxide hydrate, then (b) calculate the ‘theoretical yield’ in g of calcium peroxide hydrate that would be formed in your reaction. Show your reasoning/calculations. [4 marks]
Original post by Mooonshine
CaCO3 + H2O2 CaO2.xH2O + CO2 + H2O

Since excess hydrogen peroxide was present, the theoretical yield is based on the quantity of calcium carbonate used in the synthesis.

RMM of calcium carbonate = 72 g mol-1
Calcium carbonate used = 10.6 g Moles calcium carbonate used = 0.14623 mol [4 marks]

The number of moles of CaCO3 used is called the REACTION SCALE. How many moles of calcium peroxide hydrate will be produced from this number of moles of CaCO3 assuming that the reaction goes to completion (i.e. giving 100% of product or the ‘theoretical yield’)? Show your reasoning/calculation. [4 marks]




From your analytical results, the value of x will now be known. Using this value, (a) calculate the RMM of calcium peroxide hydrate, then (b) calculate the ‘theoretical yield’ in g of calcium peroxide hydrate that would be formed in your reaction. Show your reasoning/calculations. [4 marks]

Work out the ratio of CaCO3 to the calcium peroxide hydrate. This tells you how many moles of calcium peroxide hydrate are produced from 1 mole of CaCO3, so you can find the moles of calcium peroxide produced.
Reply 2
How do you work out the second part of the question?

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