Risermax
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#1
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#1
Please Help!

How does 3^(k+1)-3+2×3^(k+1) simplify to 3(3^(k+1)-1)?
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old_engineer
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#2
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(Original post by Risermax)
Please Help!

How does 3^(k+1)-3+2×3^(k+1) simplify to 3(3^(k+1)-1)?
Your first line of working should be to add 3^(k + 1) and 2x3^(k + 1) together.

Post your working if stuck.
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Risermax
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#3
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(Original post by old_engineer)
Your first line of working should be to add 3^(k + 1) and 2x3^(k + 1) together.

Post your working if stuck.
How do you do 3^(k+1)+6^(k+1)?
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old_engineer
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#4
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#4
(Original post by Risermax)
How do you do 3^(k+1)+6^(k+1)?
I took 2x3^(k + 1) to mean 2 x (3^(k+1)). Is it actually (2 x 3)^(k + 1)? What is the exact notation used in the question?
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Risermax
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#5
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(Original post by old_engineer)
I took 2x3^(k + 1) to mean 2 x (3^(k+1)). Is it actually (2 x 3)^(k + 1)? What is the exact notation used in the question?
Oh no I was wrong you're right but still how would you add 3^(k+1) to 2×(3^(k+1))
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davros
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#6
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#6
(Original post by Risermax)
Oh no I was wrong you're right but still how would you add 3^(k+1) to 2×(3^(k+1))
the same way you add an orange to two oranges, or x to 2x You're overthinking things here! You have "something" and another 2 lots of the "something" to add to it
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old_engineer
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#7
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#7
(Original post by Risermax)
Oh no I was wrong you're right but still how would you add 3^(k+1) to 2×(3^(k+1))
Just to paraphrase what davros said, if you let A = 3^(k + 1) then the addition you need to do can be stated as A + 2A.
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