# Hall Voltage

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#1
I read in the textbook that the Hall voltage is developed due to deviation of current to one face of the semiconductor which builds up charge on that face. As charge builds up on one face, so does the electric field and this electric field balances the magnetic field. So we can derive this equation for when equilibrium is reached: Hall voltage=BI/nte.

But when electric field starts to oppose the magnetic field, doesn't the current get less deviated? And if the current is less deviated, then there shouldn't be a build up of charge on one face anymore. Why is there still a Hall voltage when equilibrium is reached? Help plz.
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1 month ago
#2
Even though the steady-state current is undeviated, there is still a force on it from the magnetic field which is balanced by the built-up Hall field.

As an analogy, imagine a car being driven only by the left-hand side wheels, with the right-hand side ones able to turn freely. It would turn continuously in a circle unless acted on by a force pushing to radially outwards which balances the centripetal force from the wheels. In the case these are exactly equal, it would move in a straight line (but require the outward pushing force - equivalent to Hall voltage).
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