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Mathematical Proof
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beachpanda
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#1
Is anyone able to help me prove the following is true? Where x & y are positive non-zero values
![Name: Bildschirmfoto 2021-12-06 um 13.07.04.png
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I tried writing a fraction with x+y on the top and proving that it's greater than 1, but to no success. Even tried rationalising the denominator but also no luck:
![Name: Bildschirmfoto 2021-12-06 um 13.06.01.png
Views: 4
Size: 5.9 KB]()
Thankyou
I tried writing a fraction with x+y on the top and proving that it's greater than 1, but to no success. Even tried rationalising the denominator but also no luck:
Thankyou
Last edited by beachpanda; 5 months ago
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ghostwalker
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#2
(Original post by beachpanda)
Is anyone able to help me prove the following is true? Where x & y are positive non-zero values
![Name: Bildschirmfoto 2021-12-06 um 13.07.04.png
Views: 13
Size: 16.1 KB]()
I tried writing a fraction with x+y on the top and proving that it's greater than 1, but to no success. Even tried rationalising the denominator but also no luck:
![Name: Bildschirmfoto 2021-12-06 um 13.06.01.png
Views: 4
Size: 5.9 KB]()
Thankyou
Is anyone able to help me prove the following is true? Where x & y are positive non-zero values
I tried writing a fraction with x+y on the top and proving that it's greater than 1, but to no success. Even tried rationalising the denominator but also no luck:
Thankyou
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the bear
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#3
(Original post by beachpanda)
Is anyone able to help me prove the following is true? Where x & y are positive non-zero values
![Name: Bildschirmfoto 2021-12-06 um 13.07.04.png
Views: 13
Size: 16.1 KB]()
I tried writing a fraction with x+y on the top and proving that it's greater than 1, but to no success. Even tried rationalising the denominator but also no luck:
![Name: Bildschirmfoto 2021-12-06 um 13.06.01.png
Views: 4
Size: 5.9 KB]()
Thankyou
Is anyone able to help me prove the following is true? Where x & y are positive non-zero values
I tried writing a fraction with x+y on the top and proving that it's greater than 1, but to no success. Even tried rationalising the denominator but also no luck:
Thankyou
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beachpanda
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#4
(Original post by the bear)
if you let x and y both equal 1 see what happens
if you let x and y both equal 1 see what happens
(Original post by ghostwalker)
You might like to try looking for a counter-example.
You might like to try looking for a counter-example.
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the bear
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#5
(Original post by beachpanda)
I get 4<2 which isn't correct? But I've been told that x+y is greater than the other expression? (It formed part of a much longer question)
Do you know what sort of counter example? I could switch the inequality sign, or flip the fraction but I come into the same issues.
I get 4<2 which isn't correct? But I've been told that x+y is greater than the other expression? (It formed part of a much longer question)
Do you know what sort of counter example? I could switch the inequality sign, or flip the fraction but I come into the same issues.
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ghostwalker
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#6
(Original post by beachpanda)
I get 4<2 which isn't correct? But I've been told that x+y is greater than the other expression? (It formed part of a much longer question)
Do you know what sort of counter example? I could switch the inequality sign, or flip the fraction but I come into the same issues.
I get 4<2 which isn't correct? But I've been told that x+y is greater than the other expression? (It formed part of a much longer question)
Do you know what sort of counter example? I could switch the inequality sign, or flip the fraction but I come into the same issues.
As to a counter example, it's just a case of plugging some values in which make the assertion false, which is what you have done with the bear's suggestion. That's the counter-example disproving the assertion.
Last edited by ghostwalker; 5 months ago
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