When ethanamide (CH3CONH2) burns in oxygen the carbon is converted into carbon dioxide, the hydrogen is converted into water and the nitrogen forms nitrogen gas.
Substance ethanamide carbon dioxide water
Enthalpy of formation ( ) / kJ mol−1 −320 −394 −286
Using the data above, which one of the following is a correct value for the enthalpy of combustion of ethanamide?
A −1823 kJ mol−1
B −1183 kJ mol−1
C −1000 kJ mol−1
D −360 kJ mo1−1
Is the equation 2(CH3CONH2)+6O2 -> 4CO2 + 5H2O +N2
And whats to do next?
Please help, don't paste me a link to website.