# The equation of a line

#1
Find the equation of the line
Last edited by etherealblair; 4 months ago
0
4 months ago
#2
(Original post by etherealblair)
Find the equation of the line
y=mx + c

So find the gradient using m = change in y/change in x (pick 2 coordinates and do that)
Then find c, the y-intercept
Or input the values into the equation or y-y1 = m(x-x1), where x1 and y1 are the coordinates of a point on the line
0
#3
[quote=booklover1313;96484397]y=mx + c

So find the gradient using m = change in y/change in x (pick 2 coordinates and do that)
Then find c, the y-intercept
Or input the values into the equation or y-y1 = m(x-x1), where x1 and y1 are the coordinates of a point on the line

I've chosen to coordinates from the graph (0,6) and (3,9) but what do you mean by change in? Do you divide each x coordinate by the y coordinate like ( (0,6÷3,9) or 0÷6 and 3÷9. I've watched a couple videos but they haven't really helped. If you could narrow it down a little more maybe I'll understand better . I don't really understand what I have to do the answer the homework question any more help would be highly appreciated but if you can't it's fine also before I thought the answer was 4x+5=y but my hw site (mathswatch) says it's wrong so idk <33
0
4 months ago
#4
(Original post by etherealblair)
(Original post by booklover1313)
y=mx + c

So find the gradient using m = change in y/change in x (pick 2 coordinates and do that)
Then find c, the y-intercept
Or input the values into the equation or y-y1 = m(x-x1), where x1 and y1 are the coordinates of a point on the line

I've chosen to coordinates from the graph (0,6) and (3,9) but what do you mean by change in? Do you divide each x coordinate by the y coordinate like ( (0,6÷3,9) or 0÷6 and 3÷9. I've watched a couple videos but they haven't really helped. If you could narrow it down a little more maybe I'll understand better . I don't really understand what I have to do the answer the homework question any more help would be highly appreciated but if you can't it's fine also before I thought the answer was 4x+5=y but my hw site (mathswatch) says it's wrong so idk <33
So you can look at the gradient as being the rate of the increase or decrease of a line. The line in the question is going up, so we can think 'for every 1 along, how many up do we go?'. That is what the gradient is telling us. So if we had a gradient of 2, we would see that if we went along by 1, so our x value increased by 1, we would go up by 2, so our y value increases by 2.
If we look at our line, you chose the points (0,6) and (3,9).
Between these points, our x value has increased by 3, from 0 to 3, and our y value has also increased by 3, from 6 to 9.
The equation for finding the gradient is 'change in y' - so this is how much up or down we have gone, divided by the 'change in x' - which is how far along we have gone.
So we would put in gradient (symbol m):
m = (change in y)/(change in x) = (9-6)/(3-0) = 3/3 = 1
So do you see that our change in the y has been positive 3, from 6 to 9. To find that difference, we did the 9-6 on the top of the fraction.
We can now see that our gradient is 1, which means that for every 1 we go along, we will also go 1 up.
To find the y intercept, we can look at the graph. The y intercept is when the line crosses the y axis. We can see that is when the value for x is 0, and the value of y is 6. So the point (0,6).
Therefore our y intercept is going to be 6.
y = mx +c , so we found that m = 1 and c = 6,
so y = 1x + 6 = x + 6

Using the other equation of y-y1 = m(x-x1) - this is good when it is a bit more complicated and we can't see the y intercept clearly
Let's use the point (3,9), so our x1 value is 3 and our y1 value is 9, m is still 1
y-y1 = m(x-x1)
y-9=1(x-3)
y-9=x-3 [add 9 to both sides]
y=x + 6, which is the same as we had before.

Does that make sense? If you have any more questions, just ask
2
#5
(Original post by booklover1313)
So you can look at the gradient as being the rate of the increase or decrease of a line. The line in the question is going up, so we can think 'for every 1 along, how many up do we go?'. That is what the gradient is telling us. So if we had a gradient of 2, we would see that if we went along by 1, so our x value increased by 1, we would go up by 2, so our y value increases by 2.
If we look at our line, you chose the points (0,6) and (3,9).
Between these points, our x value has increased by 3, from 0 to 3, and our y value has also increased by 3, from 6 to 9.
The equation for finding the gradient is 'change in y' - so this is how much up or down we have gone, divided by the 'change in x' - which is how far along we have gone.
So we would put in gradient (symbol m):
m = (change in y)/(change in x) = (9-6)/(3-0) = 3/3 = 1
So do you see that our change in the y has been positive 3, from 6 to 9. To find that difference, we did the 9-6 on the top of the fraction.
We can now see that our gradient is 1, which means that for every 1 we go along, we will also go 1 up.
To find the y intercept, we can look at the graph. The y intercept is when the line crosses the y axis. We can see that is when the value for x is 0, and the value of y is 6. So the point (0,6).
Therefore our y intercept is going to be 6.
y = mx +c , so we found that m = 1 and c = 6,
so y = 1x + 6 = x + 6

Using the other equation of y-y1 = m(x-x1) - this is good when it is a bit more complicated and we can't see the y intercept clearly
Let's use the point (3,9), so our x1 value is 3 and our y1 value is 9, m is still 1
y-y1 = m(x-x1)
y-9=1(x-3)
y-9=x-3 [add 9 to both sides]
y=x + 6, which is the same as we had before.

Does that make sense? If you have any more questions, just ask

Thank you so much for the explanation! I understand this now and I can finally finish the last piece of homework I was struggling on! Thank youuu!!! I hope you have a wonderful day/night! You're the best! <33
1
4 months ago
#6
(Original post by etherealblair)
Thank you so much for the explanation! I understand this now and I can finally finish the last piece of homework I was struggling on! Thank youuu!!! I hope you have a wonderful day/night! You're the best! <33
You’re very welcome, I’m glad I could help
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