Back
to top
Finding Energy Density from Stress-Strain graph
Watch this threadPage 1 of 1
Go to first unread
Skip to page:
Aleksander Krol
Badges:
13
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#1
Stress x Strain gives us Energy density (Jm-3).
![Name: Screenshot_20220117_162801.jpg
Views: 21
Size: 71.6 KB]()
In this case, should I use 0.5 x Stress(y) x Strain(x) to find Energy Density?
Because area under stress-strain graph gives energy density.
Case 2:
If the graph was curved, I will have to count the no. of boxes under the graph. And then look for stress and strain for 1 box. Multiply Stress with Strain, which will give me the energy density for 1 box.
Then multiply this value with the total no. of boxes under the graph to find the total energy demsity for the whole graph, right?
Just want to clear my understanding.
In this case, should I use 0.5 x Stress(y) x Strain(x) to find Energy Density?
Because area under stress-strain graph gives energy density.
Case 2:
If the graph was curved, I will have to count the no. of boxes under the graph. And then look for stress and strain for 1 box. Multiply Stress with Strain, which will give me the energy density for 1 box.
Then multiply this value with the total no. of boxes under the graph to find the total energy demsity for the whole graph, right?
Just want to clear my understanding.
Last edited by Aleksander Krol; 3 months ago
0
reply
Stonebridge
Badges:
13
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#2
Report
#2
(Original post by Aleksander Krol)
Stress x Strain gives us Energy density (Jm-3).
![Name: Screenshot_20220117_162801.jpg
Views: 21
Size: 71.6 KB]()
In this case, should I use 0.5 x Stress(y) x Strain(x) to find Energy Density?
Because area under stress-strain graph gives energy density.
Case 2:
If the graph was curved, I will have to count the no. of boxes under the graph. And then look for stress and strain for 1 box. Multiply Stress with Strain, which will give me the energy density for 1 box.
Then multiply this value with the total no. of boxes under the graph to find the total energy demsity for the whole graph, right?
Just want to clear my understanding.
Stress x Strain gives us Energy density (Jm-3).
In this case, should I use 0.5 x Stress(y) x Strain(x) to find Energy Density?
Because area under stress-strain graph gives energy density.
Case 2:
If the graph was curved, I will have to count the no. of boxes under the graph. And then look for stress and strain for 1 box. Multiply Stress with Strain, which will give me the energy density for 1 box.
Then multiply this value with the total no. of boxes under the graph to find the total energy demsity for the whole graph, right?
Just want to clear my understanding.
That is 0.5 x stress x strain for a triangle. That gives the strain energy density for that particular value of stress or strain.
If the graph is not a straight line you have to find the area by other means. (Counting the boxes is one way.)
The energy density is still the total area under the graph. Not half the area.
Last edited by Stonebridge; 3 months ago
0
reply
lordaxil
Badges:
11
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#3
Report
#3
Yes, that's essentially right, although only strictly true as the size of boxes tend to zero. If you are familiar with integral calculus then what you want to say can be expressed more precisely as 
[referring to OP]
[referring to OP]
Last edited by lordaxil; 3 months ago
0
reply
X
Page 1 of 1
Go to first unread
Skip to page:
Quick Reply
