# Need help with maths

#1
0
4 months ago
#2
(Original post by Matheen1)
How far have you got?
0
#3
(Original post by Muttley79)
How far have you got?
I think I’ve found the two tangents
0
4 months ago
#4
(Original post by Matheen1)
1. differentiate equation
2. equate the differentiated equation to 4 as u wanna find the x coordinates for the gradient (if that makes sense?)
3. then once u have your x coordinates sub these into original equation
4. now u must have a gradient (of 4) and 2 coordinates and form te equations
0
4 months ago
#5
(Original post by Matheen1)
I think I’ve found the two tangents
The first three lines are correct but when you put dy/dx = 4 you need to collect the '4' on the right to get a quadratic = 0. Only then can you solve ...
0
#6
(Original post by Muttley79)
The first three lines are correct but when you put dy/dx = 4 you need to collect the '4' on the right to get a quadratic = 0. Only then can you solve ...
Is this correct (corrections are in green)!
0
4 months ago
#7
(Original post by Matheen1)
Is this correct (corrections are in green)!
Check the 'c' in the x = 2 tangent
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#8
(Original post by Muttley79)
Check the 'c' in the x = 2 tangent
Oh thanks I just realised it’s meant to be -11 instead of 11.
0
4 months ago
#9
(Original post by Matheen1)
Oh thanks I just realised it’s meant to be -11 instead of 11.
Yes - looks OK now
0
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