I need help with Maths

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Matheen1
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#1
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#1
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Size:  78.9 KB I’ve done 5a now I just need help with 5b please
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Matheen1
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Size:  104.5 KB This is what I got for 5a.
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mqb2766
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a) looks about right
https://www.desmos.com/calculator/2x8jxmsu6j

So find the point(s) of intersection between the curve and the normal and show there is only a single solution (that point).
Last edited by mqb2766; 4 months ago
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Sharzz
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(Original post by Matheen1)
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Size:  78.9 KB I’ve done 5a now I just need help with 5b please
equate the equation of the normal to that of the original graph. You should only get one solution for x which is x=1 which is stated in the question showing there is no other intersection point and so no other points where they meet.
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Abraham_Otaku
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well one would be to firstly equate the two equations.. and then rearrange to get 6x^3+4x^2-10.. you could use the discriminant....provided its a quadratic function.. but its not.. so you can't. Which then leavesway you to long division(at least that's a method I'm aware you could use).. and as its given that the solution is x=1.. a factor would be (x-1) and so you divide
6x^3+4x^2-10 with x-1.. and you then obtain a quadratic function and your original (x-1) factor.. you then use the discriminant for the quadratic function, which shows that the discriminant is a negative value.. and so only one solution exists... which is your x=1, hence the normal only meets the curve once... hope that helped
(Original post by Matheen1)
Name:  C6BF3C7C-C40F-4099-BA93-5F2D1C5A282E.jpeg
Views: 12
Size:  104.5 KB This is what I got for 5a.
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