I need help with Integration question

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Matheen1
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#1
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#1
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mqb2766
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#2
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#2
(Original post by Matheen1)
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As usual, what have you done?
It does help to upload your working in the OP.
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Matheen1
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(Original post by mqb2766)
As usual, what have you done?
It does help to upload your working in the OP.
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mqb2766
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(Original post by Matheen1)
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Thats not quite what the question is asking.
Sketch the curve and the boundary of the integration problem and upload?
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Matheen1
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#5
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#5
(Original post by mqb2766)
Thats not quite what the question is asking.
Sketch the curve and the boundary of the integration problem and upload?
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mqb2766
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Which part are you working out?
Also note your previous working misses out the lower limit part at the end.
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Matheen1
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#7
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#7
I’m trying to find the enclosed area in the middle.
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mqb2766
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(Original post by Matheen1)
I’m trying to find the enclosed area in the middle.
Agreed, you've only done from x = 1/2 .. 2 though, you're missing a bit.
Also note that your working doesn't include the lower or upper(?) limit in the previous post. The area should not be negative.
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Matheen1
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#9
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#9
(Original post by mqb2766)
Agreed, you've only done from x = 1/2 .. 2 though, you're missing a bit.
Also note that your working doesn't include the lower or upper(?) limit in the previous post. The area should not be negative.
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Matheen1
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#10
(Original post by Matheen1)
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I really don’t know what to do.
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mqb2766
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#11
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#11
(Original post by Matheen1)
I really don’t know what to do.
3/2 looks about right for 1/2..2. So what about the bit from 0..1/2.
Id bet you do know how to get that area.
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Matheen1
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#12
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#12
(Original post by mqb2766)
3/2 looks about right for 1/2..2. So what about the bit from 0..1/2.
Id bet you do know how to get that area.
Wait how did u get 0…1/2?
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mqb2766
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#13
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#13
(Original post by Matheen1)
Wait how did u get 0…1/2?
You want to find the area enclosed by the axes, the curve and x=2 and y=4. Do a sketch, rather than desmos, and shade in the area youve already calculated. Which bit is missing?
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Matheen1
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#14
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#14
(Original post by mqb2766)
You want to find the area enclosed by the axes, the curve and x=2 and y=4. Do a sketch, rather than desmos, and shade in the area youve already calculated. Which bit is missing?
Isn’t the part that is left meant to be 0…2 I just can’t get my head around why it is 0…1/2
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mqb2766
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#15
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#15
(Original post by Matheen1)
Isn’t the part that is left meant to be 0…2 I just can’t get my head around why it is 0…1/2
Tbh, Id forget about desmos (its good, but just sketch it on your paper as you would do in an exam).
Shade the area youve calculated, noting the limits youve used.
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bexxr
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#16
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#16
Wouldn't this be the correct way to draw the graph (R = area)?

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