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I need help with Integration question
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Matheen1
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#1
mqb2766
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Matheen1
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#3
(Original post by mqb2766)
As usual, what have you done?
It does help to upload your working in the OP.
As usual, what have you done?
It does help to upload your working in the OP.
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mqb2766
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#4
Sketch the curve and the boundary of the integration problem and upload?
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Matheen1
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#5
(Original post by mqb2766)
Thats not quite what the question is asking.
Sketch the curve and the boundary of the integration problem and upload?
Thats not quite what the question is asking.
Sketch the curve and the boundary of the integration problem and upload?
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mqb2766
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#6
Which part are you working out?
Also note your previous working misses out the lower limit part at the end.
Also note your previous working misses out the lower limit part at the end.
Last edited by mqb2766; 3 months ago
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Matheen1
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mqb2766
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#8
(Original post by Matheen1)
I’m trying to find the enclosed area in the middle.
I’m trying to find the enclosed area in the middle.
Also note that your working doesn't include the lower or upper(?) limit in the previous post. The area should not be negative.
Last edited by mqb2766; 3 months ago
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Matheen1
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#9
(Original post by mqb2766)
Agreed, you've only done from x = 1/2 .. 2 though, you're missing a bit.
Also note that your working doesn't include the lower or upper(?) limit in the previous post. The area should not be negative.
Agreed, you've only done from x = 1/2 .. 2 though, you're missing a bit.
Also note that your working doesn't include the lower or upper(?) limit in the previous post. The area should not be negative.
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Matheen1
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mqb2766
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#11
(Original post by Matheen1)
I really don’t know what to do.
I really don’t know what to do.
Id bet you do know how to get that area.
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Matheen1
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#12
(Original post by mqb2766)
3/2 looks about right for 1/2..2. So what about the bit from 0..1/2.
Id bet you do know how to get that area.
3/2 looks about right for 1/2..2. So what about the bit from 0..1/2.
Id bet you do know how to get that area.
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mqb2766
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#13
(Original post by Matheen1)
Wait how did u get 0…1/2?
Wait how did u get 0…1/2?
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Matheen1
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#14
(Original post by mqb2766)
You want to find the area enclosed by the axes, the curve and x=2 and y=4. Do a sketch, rather than desmos, and shade in the area youve already calculated. Which bit is missing?
You want to find the area enclosed by the axes, the curve and x=2 and y=4. Do a sketch, rather than desmos, and shade in the area youve already calculated. Which bit is missing?
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mqb2766
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#15
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#15
(Original post by Matheen1)
Isn’t the part that is left meant to be 0…2 I just can’t get my head around why it is 0…1/2
Isn’t the part that is left meant to be 0…2 I just can’t get my head around why it is 0…1/2
Shade the area youve calculated, noting the limits youve used.
Last edited by mqb2766; 3 months ago
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bexxr
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