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Nucleophilic Substitution Reaction (between Alkyl halide & Ammonia)
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Aleksander Krol
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Can someone tell me if that's how tetraethylammonium bromide is formed?
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I'm not sure about the structure of tetraethylammonium bromide.
Is this what happens in the last step?
Carbon and Bromine bond breaks by homolytic fission.
Nitrogen has a positive charge, because it lost an electron to Bromine. Bromine becomes negative, by gaining the electron.
I'm not sure about the structure of tetraethylammonium bromide.
Is this what happens in the last step?
Carbon and Bromine bond breaks by homolytic fission.
Nitrogen has a positive charge, because it lost an electron to Bromine. Bromine becomes negative, by gaining the electron.
Last edited by Aleksander Krol; 3 months ago
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Fibonacci28
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#2
That is the correct structure,
I'd personally use curly arrows if I wanted to show the mechanism. So for example with the first step: one from the electron pair on the nitrogen to the carbon and then from the C-B bond to the bromine
Otherwise looks good
I'd personally use curly arrows if I wanted to show the mechanism. So for example with the first step: one from the electron pair on the nitrogen to the carbon and then from the C-B bond to the bromine
Otherwise looks good
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scimus63
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