Improper integrals

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User39339
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#1
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#1
Deleeeted
Last edited by User39339; 2 months ago
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mqb2766
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#2
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If you divide the numerator and denominator of the fraction by x, what do you get and what can you say about it as x->inf?

Alternatively, write it as
quotient + remainder/(1+x)
Last edited by mqb2766; 3 months ago
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mqb2766
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#3
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(Original post by User39339)
Oh I see so it's ln|2 — 1/(X+1)|
But I don't understand what happens to xas it tends to infinity would it be zero or surely its undefined
What is the value of each term as x->inf?
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mqb2766
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#4
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(Original post by User39339)
1/inf?
What is
2
as x-> inf? What is
-1/(x+1)
as x-> inf? Add them.
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simon0
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#5
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(Original post by User39339)
1/inf?
HINT: What is the "limit" as x tends to infinity.
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