# Problem....Watch

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#1
Some toys are sold at all the same prices, were brought for £40. If the cost of each toy had been £1 more, then two fewer toys could have been brought. Find the no. of toys that were brought. TY!!
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14 years ago
#2
Let n = number of toys and let p=price of each toy

Therefore, np = 40
Which gives, p = 40/n

Also, (n-2)(p+1) = 40
But p = 40/n
So, (n-2)(40/n + 1) = 40
n^2 -2n - 80 = 0
(n+8)(n-10) = 0

So n = -8 or n=10

Since n is positive, n must be 10
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