UKMT Maclaurin Olympiad 2022: Maths

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Wormscarf67
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#1
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#1
How did everyone find it? I didn't get q5 or 6, and was wondering if people had any insights?
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epii+1=0
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#2
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#2
(Original post by Wormscarf67)
How did everyone find it? I didn't get q5 or 6, and was wondering if people had any insights?
(i don't think we're allowed to discuss olympiads yet cuz china still have to do it tomorrow)
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rasem005
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#3
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#3
(Original post by Wormscarf67)
How did everyone find it? I didn't get q5 or 6, and was wondering if people had any insights?
I struggled with the first few questions. I’d appreciate some help understanding how to do them?
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mqb2766
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#4
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#4
As above, the exam over two days Thursday / Friday so pls dont discuss it.
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mqb2766
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#5
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#5
(Original post by Cridplbn)
Is the exam over now because I would like to see which ones I got right.
Id guess so. They generally release paper/solutions the following day which would be Monday in this case, but the exam is over so ...
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_wxyz_
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#6
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#6
I don't want to discuss it in detail yet until the paper and sols are out, but my solution for Q5 was not exactly inaccessible but it was pretty obscure (involving an interesting property of squares) - I assume there are more obvious ways of solving part (b), but I couldn't think of any alternative solutions. Q6 was easier imo but still a little tricky

edit: pretty sure its over so for q5 you can use the fact that b^2 and the two discriminants form an arithmetic sequence and for q6 a construction extending a line does the job
Last edited by _wxyz_; 3 months ago
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Jam.123
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#7
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#7
What about for Q1? Me and the other person who did it from my school are both pretty sure it was impossible because the m% of water and losing (m-5)% of this to reach 50% water just doesn't work in our opinion
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_wxyz_
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#8
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#8
(Original post by Jam.123)
What about for Q1? Me and the other person who did it from my school are both pretty sure it was impossible because the m% of water and losing (m-5)% of this to reach 50% water just doesn't work in our opinion
try m=80

4 parts water to 1 part fruit becomes 1:1
(this comes from the quadratic m^2 - 205m + 10000 btw)
Last edited by _wxyz_; 3 months ago
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Jam.123
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#9
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#9
So m=80%:
80% - 80%(75%) = 20%

I feel like I'm just being stupid though
Last edited by Jam.123; 3 months ago
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_wxyz_
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#10
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#10
(Original post by Jam.123)
So m=80%:
80% - 80%(75%) = 20%

I feel like I'm just being stupid though
20% was the original weight of the non-water mass, so the new ratio is 1:1
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Jam.123
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#11
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#11
(Original post by _wxyz_)
20% was the original weight of the non-water mass, so the new ratio is 1:1
Ohhhh, I feel so stupid now because of forgetting to account for mass being lost altogether.
Thanks though
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cardtricks
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#12
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#12
how did you get that quadratic?Personally, I got m^2 - 105m 5000 which yielded no results so i was unable to solve the problem
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cardtricks
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#13
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#13
(Original post by cardtricks)
how did you get that quadratic?Personally, I got m^2 - 105m 5000 which yielded no results so i was unable to solve the problem
sry m^2 - 105m + 5000
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Jam.123
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#14
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#14
20m^2-41m+20=0 is the final quadratic you'd need

(Original post by cardtricks)
sry m^2 - 105m + 5000
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_wxyz_
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#15
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#15
(Original post by Cridplbn)
what was the explanation behind 6, I only had a couple of minutes to comprehend it and the only instinct I had was to use the abc conjecture. Any explanations
extend DE hit the circle again at P and then triangles CEP and BPC are similar, which gives you that EC/CP = 1/2 and then since triangles DBE and CPE are similar so DE/DB = 1/2
Last edited by _wxyz_; 3 months ago
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Jam.123
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#16
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#16
(Original post by Jam.123)
20m^2-41m+20=0 is the final quadratic you'd need
because m-m(m-0.05)=1-m
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Cridplbn
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#17
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#17
Is the exam over if so when do we get results?
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_wxyz_
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#18
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#18
(Original post by Cridplbn)
For question 2 we’re the answers 0 and 1
can you remind me what q2 was?
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_wxyz_
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#19
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#19
(Original post by Cridplbn)
Took a quick snap
yeah, pretty sure you're right (i assume you used parity proof)
Last edited by _wxyz_; 3 months ago
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Jam.123
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#20
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#20
expand (x+1)(x^2-x+1)
and then use this to find all the places where a power of two is one more than a cube
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