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Why is the answer b and how do u get there

Chem85275433-3165-4DD5-B865-326023DEDDD7.jpeg
(edited 2 years ago)
Reply 1
As you have 2 mol NaN3, you produce 3 mol N2 in the first reaction.
You have also produced 2 mol Na.
We know 10 Na produces 1 mol N2 in the secondary reaction.
However, as we only have 2 mol, we can only produce 2/10 mol N2.
Altogether we have: 3 + 0.2 = 3.2 mol N2
3.2 x Avagadro's constant (6.022 x 10^23) = 19.27 x 10^23 molecules
19.27 x 10^23 = 1.927 x 10^24 = 1.93 x 10^24 molecules

Hope that helps :smile:
Reply 2
Why does the 3n2 react with the 10na and what do u do about the k in the second equation
Reply 3
Original post by Roxibox123
Why does the 3n2 react with the 10na and what do u do about the k in the second equation


No N2 reacts with Na at any point.
As we are focussed on the production of N2 only, we do not need to worry about K, we can just assume there is enough to react fully unless stated otherwise I believe.

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