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# a very quic probability question. watch

1. we have a regular hexagon with lines joining opposite faces. 7 vertices - the centre and the 6 corners. someone goes on a random walk between vertices. A and B are adjacent corners, C is the centre vertex. write h_i = P(returns to A before visiting C, given we start at i).

why does h_A = (2/3)h_B ?
2. Let D be the vertex on the other side of A. What is h_D in terms of h_B?
3. (Original post by SimonM)
Let D be the vertex on the other side of A. What is h_D in terms of h_B?
it is h_B, by symmetry.

and h_A = 1/3 h_B + 1/3 h_D + 0.

oh yeah kool.
4. (Original post by Chewwy)
it is h_B, by symmetry.

and h_A = 1/3 h_B + 1/3 h_D + 0.

oh yeah kool.
Source?

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