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# A bit of help appreciated.. watch

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1. Don't really know what to do here :

"At a particular point of the curve the equation of the normal is . Find the value of constant c."

I know that 'cos the gradient of the normal is 1, the gradient of the tangent is -1, but that's it really.

Thanks
2. Nope, the gradient of the normal isn't 1. Get the equation in the form y = mx + b and you'll see what the gradient of the normal is.
Once you've done that:
Spoiler:
Show

Differentiate y = 5x^2 - 12x + 1 and set dy/dx equal to the gradient of the tangent. You'll have x. You can get y, so you can find c.
3. Yeah thanks, I realised that just after I posted. Sorry!

Thanks a lot.

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Updated: November 8, 2008
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