Organic chemistry, dehydrating a carbon ring

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Aurora.j
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How do I riddle this one out?
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tony_dolby
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Quite a tricky question! You have four carbons in the ring and one oxygen. I would number the carbons on both the sorbitol and the uncompleted sorbitan.

Carbons 1- 4 form part of the ring and five and six are not used and hang off the side. The OH group on carbon 1 has gone because the O is used to join carbons 1 and 4 together. There is no longer an OH on carbon 4 because it has left, becoming water. The other OHs are unused and remain in their positions. I don't know what the mark scheme says, but this reaction produces three isomers that fulfill the remits of the question.

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