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    Find the general solution to dy/dx = (1+y^2)/(tanx)

    Now i rearranged that to dy/(1+y^2) = dx/tanx and was about to integrate both sides and while the left hand side is easy - tan^-1x - I realised I have no idea what to do with the right Any hints would be appreciated.
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    Ln(sinx)

    Remember 1/Tanx=Cotx=Cosx/Sinx
    Sinx=f(x) Cosx=f'(x)

    Also make sure you use arctany not arctanx for the left hand
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    Yeah that's what I meant XD

    Thanks, i didn't make that connection.
 
 
 
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