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# Differential equation (advanced higher maths) watch

1. Find the general solution to dy/dx = (1+y^2)/(tanx)

Now i rearranged that to dy/(1+y^2) = dx/tanx and was about to integrate both sides and while the left hand side is easy - tan^-1x - I realised I have no idea what to do with the right Any hints would be appreciated.
2. Ln(sinx)

Remember 1/Tanx=Cotx=Cosx/Sinx
Sinx=f(x) Cosx=f'(x)

Also make sure you use arctany not arctanx for the left hand
3. Yeah that's what I meant XD

Thanks, i didn't make that connection.

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Updated: November 8, 2008
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