partial pressure-

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shreya_2003
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i put initially n2 was 0.25 and H2 was 0.75
not sure if mol fraction is done correct since i did 0.25/1
and had NH3 as 0 at start
partial pressure for N2= 0.25 x 4x10^5= 100000?
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Pigster
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(Original post by shreya_2003)
i put initially n2 was 0.25 and H2 was 0.75
not sure if mol fraction is done correct since i did 0.25/1
and had NH3 as 0 at start
partial pressure for N2= 0.25 x 4x10^5= 100000?
That looks to be a tricky one at first, but actually it isn't too tricky really.

If you started with 1 bar of N2 and 3 bar H2 and after equilibrium is set up, you've got 0.1 bar of N2, that means 0.9 bar has reacted.

The rest is a fairly simple ICE table.
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