Physics question a level help pleaseeee

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Htx_x346
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Sorry for the number of questions but i have my exam soon so thats why xName:  59EDBF76-7E0B-4BA5-A963-BD36EC3C0BBD.jpeg
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For part ii I dont really understand why the centripetal force affects the friction because the forces are perpendicular to each other?

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I also don’t understand why they havent included the normal reaction force of the wall on the person for this question?
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Htx_x346
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And lastly i dont really understand how the answer is the fourth option? Surely the coin feels the centripetal force?
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tarmac-the-cat
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The coin had been 'dropped'. It will not follow the circular path now. There is nothing accelerating it to the centre of the circle.
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tarmac-the-cat
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Friction between surfaces is larger if the surfaces are pushed together. Try it by rubbing your hands together. When the ride slows down there is less centripetal force, hence less friction.
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DylanW21
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For part ii.The frictional force between the person and wall is equal to the coefficient of friction multiplied by the normal reaction force (F= μR). As R decreases F decreases proportionally (as coefficient of friction is constant).
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tarmac-the-cat
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It does say 'normal reaction' in the mark scheme
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Htx_x346
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(Original post by tarmac-the-cat)
The coin had been 'dropped'. It will not follow the circular path now. There is nothing accelerating it to the centre of the circle.



I dont understand why it doesnt feel the centripetal force



(Original post by tarmac-the-cat)
Friction between surfaces is larger if the surfaces are pushed together. Try it by rubbing your hands together. When the ride slows down there is less centripetal force, hence less friction.
Oh okay

(Original post by DylanW21)
For part ii.The frictional force between the person and wall is equal to the coefficient of friction multiplied by the normal reaction force (F= μR). As R decreases F decreases proportionally (as coefficient of friction is constant).
Ohhh okay thanks

(Original post by tarmac-the-cat)
It does say 'normal reaction' in the mark scheme
Thank you, i didnt notice that
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Ethanity007
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As the coin is dropped, there is no longer a Normal force (previously provided by man that is in contact with it) acting on it to provide the centripetal force it requires to stay in circular motion.
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Htx_x346
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(Original post by Ethanity007)
As the coin is dropped, there is no longer a Normal force (previously provided by man that is in contact with it) acting on it to provide the centripetal force it requires to stay in circular motion.
Thank youu!
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