# Venn diagrams

#1
How is P(AUB) = P (A) + p(B) - p(AnB).

I dont get why because the minus p(AnB) means ur taking away the intersection part?
0
4 weeks ago
#2
(Original post by Moonlight352)
How is P(AUB) = P (A) + p(B) - p(AnB).

I dont get why because the minus p(AnB) means ur taking away the intersection part?
P(A U B) is the entire inside of the venn diagram. If you add P(A) and the P(B) then you are essentially adding the intersection part twice as P(A) and P(B) both contain the intersection bit. To make up for this you can take away one lot of the intersection P(AnB) to get what P(A U B) is.
3
#3
(Original post by Skiwi)
P(A U B) is the entire inside of the venn diagram. If you add P(A) and the P(B) then you are essentially adding the intersection part twice as P(A) and P(B) both contain the intersection bit. To make up for this you can take away one lot of the intersection P(AnB) to get what P(A U B) is.
Thank you!!!
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