Decision Maths - Bin Packing

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Cupcakes12
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#1
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#1
I've done this question
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And I am a bit confused about the answer for part b.

The worked solutions say:
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but I put the 36 in the same bin as 42, and I don't know why they did not.

This made my final answer:
bin 1 = 47, 33
bin 2 = 42, 36
bin 3 = 41, 31
bin 4 = 27, 24, 18
bin 5 = 16, 12

Is my answer just an alternative correct version or have I done it wrong?
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Fibonacci28
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#2
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#2
I've also got what you have so I'd say you're correct. I can't understand how the mark scheme has got the answer it has, maybe talk to your teacher about it? Is this a textbook question because it's not unknown for the answers in them to be wrong
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PerpetualAgony
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#3
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I agree with Fibonnaci, what you've done is absolutely correct. Mark schemes definitely have the tendency to have mistakes, I know my textbooks had mistakes on almost every exercise and even some of the content explanations (wonderful way to screw home learners over!) There's no 'alternative' solution to this question, they've just gotten it wrong (even if the answer is the same they clearly didn't do the method correctly).
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PerpetualAgony
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#4
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(Original post by PerpetualAgony)
I agree with Fibonnaci, what you've done is absolutely correct. Mark schemes definitely have the tendency to have mistakes, I know my textbooks had mistakes on almost every exercise and even some of the content explanations (wonderful way to screw home learners over!) There's no 'alternative' solution to this question, they've just gotten it wrong (even if the answer is the same they clearly didn't do the method correctly).
They probably skimmed over too quickly and therefore incorrectly dismissed the fact that 42 and 36 don't superpass the maximum amount the bin can hold. I've done that mistake before too.
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Cupcakes12
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#5
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#5
(Original post by Fibonacci28)
I've also got what you have so I'd say you're correct. I can't understand how the mark scheme has got the answer it has, maybe talk to your teacher about it? Is this a textbook question because it's not unknown for the answers in them to be wrong
(Original post by PerpetualAgony)
I agree with Fibonnaci, what you've done is absolutely correct. Mark schemes definitely have the tendency to have mistakes, I know my textbooks had mistakes on almost every exercise and even some of the content explanations (wonderful way to screw home learners over!) There's no 'alternative' solution to this question, they've just gotten it wrong (even if the answer is the same they clearly didn't do the method correctly).
Thank you!!! It is from the Pearson textbook.
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Fibonacci28
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#6
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#6
(Original post by Cupcakes12)
Thank you!!! It is from the Pearson textbook.
Quite possible for it to be an error then
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