# centripetal acceleration formula derivation...

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#1
I'll attach the file below..
0
#2
what do they even mean by the sinthetha/thetha =1 as thetha tends to 0.. I think its something to do with the fact that for very small values of angles.. sinthetha=thetha, but not sure.....help.
Last edited by Abraham_Otaku; 4 weeks ago
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4 weeks ago
#3
Linear expansion. You can express a sine function via the form If the value of is very nearly zero, you can see that the above expression will tend to the limit 0
#4
ohh i see.. Thanks.
oh yeah also.. what if the angle is 0 degrees as opposed to just tending towards 0.. wouldn't that mean that in the derivation, centripetal acceleration is infinite?..
0
4 weeks ago
#5
(Original post by Abraham_Otaku)
ohh i see.. Thanks.
oh yeah also.. what if the angle is 0 degrees as opposed to just tending towards 0.. wouldn't that mean that in the derivation, centripetal acceleration is infinite?..
Look at your expression. If theta goes to zero, then you have a division of theta over theta- aka unity. Iirc you discuss taking limits in A-Level mathematics.
Last edited by Callicious; 4 weeks ago
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#6
(Original post by Callicious)
Look at your expression. If theta goes to zero, then you have a division of theta over theta- aka unity. Iirc you discuss taking limits in A-Level mathematics.
Based on your reply.. I feel as if the answer is really obvious.. still don't get it though.
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4 weeks ago
#7
(Original post by Abraham_Otaku)
ohh i see.. Thanks.
oh yeah also.. what if the angle is 0 degrees as opposed to just tending towards 0.. wouldn't that mean that in the derivation, centripetal acceleration is infinite?..
sin(x)/x is undefined if x is equal to 0, but the limit as x goes to 0 is 1 - i.e. gets arbitrarily close to 1 without being equal.
Note that undefined doesn't mean infinite either.
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#8
(Original post by Sinnoh)
sin(x)/x is undefined if x is equal to 0, but the limit as x goes to 0 is 1 - i.e. gets arbitrarily close to 1 without being equal.
Note that undefined doesn't mean infinite either.
I see. Thanks 0
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