The Student Room Group

alevel chemistry

A solution of a metal carbonate, M2CO3, was prepared by dissolving 7.46 g of the anhydrous solid in water to give
1000 cm3
of solution. 25.0 cm3
of this solution reacted with 27.0 cm3
of 0.100 mol dm-3 hydrochloric acid.
Calculate the relative formula mass of M2CO3 and hence the relative atomic mass of the metal M.
Original post by akxx223
A solution of a metal carbonate, M2CO3, was prepared by dissolving 7.46 g of the anhydrous solid in water to give
1000 cm3
of solution. 25.0 cm3
of this solution reacted with 27.0 cm3
of 0.100 mol dm-3 hydrochloric acid.
Calculate the relative formula mass of M2CO3 and hence the relative atomic mass of the metal M.


What have you tried, so far?
So first you'd work out the number of moles of HCl, which should be 2.7x10-3. Half as many moles of M2CO3 reacted, so thats 1.35x10-3. Multiply that by 40 to get the number of moles in the full 1000cm3. Then you can use n=m/mr to get the mr of the compound.

Quick Reply

Latest