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# Trig questions - help watch

1. could someone differentiate
3(5-2x)^5

i have an answer but need to check it thnks.
i need to find dx/dy instead of dx/dy.

do you just put it over 1
2. Yes, just 1 over dy/dx.
3. -30(5-2x)^4 = dy/dx i think
4. (Original post by Rbates1)
-30(5-2x)^4 = dy/dx i think
yeh i got this too. Do i just put 1 over it to find dx/dy
5. it then says differentiate (still dx/dy)

1 over 3x-5
is it just 3? doesnt seem right lol
6. its

so that equal (3x-5)^(-1)
7. dy/dx = 2 over -3(3x-5) ??

ps how can i write in the maths format
8. (Original post by Hrov)
ps how can i write in the maths format
LaTeX

I have it bookmarked because I can't be arsed memorizing some of the weirder arguments.
9. ok thanks

i know its the quotient rule but i want to make sure im doing it write, what is dy/dx of

i got

but dont have a clue of its right
10. (Original post by Hrov)
ok thanks

i know its the quotient rule but i want to make sure im doing it write, what is dy/dx of

i got

but dont have a clue of its right
You have messed up the signs in the numerator of your answer.

You don't have to use quotient rule here if you don't want to.

Spoiler:
Show
11. (Original post by Mr M)
You have messed up the signs in the numerator of your answer.

You don't have to use quotient rule here if you don't want to.

Spoiler:
Show
thanks i got it in the end

would

differentiate to
12. no
13. (Original post by D-Day)
no
oh well what is the correct answer, ive done it twice and get that answer, must be going wrong somewhere
14. The derivative of cotangent is
15. ok
16. (Original post by D-Day)
The derivative of cotangent is
???

17. Chain rule.

edit: What Mr M said.
18. (Original post by D-Day)

Chain rule.

edit: What Mr M said.
Lol: I said nothing!

I decided to remove it as it sounded a bit rude.
19. (Original post by D-Day)

Chain rule.

edit: What Mr M said.
so i just missed the ^2 off???

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