Turn on thread page Beta
    • Thread Starter

    okay here is results from juice from concentrate tested:

    Volume of juice required to decolourise 1cm^3 of 1% DCPIP solution/cm^3:
    (three trials) 3ml, 3.3ml and 3.2ml

    how could i caculate the mass of the juice from concentration that is required to decolourise 1cm^3 of the DCPIP solution? in mg cm^3.
    1% of vitamin C solution contains 10mg of citamin c in 1.0cm^3

    Sorry, you've made things look quite confused.

    Did you mean in 1mL of orange juice there's 10mg of vitamin C? If that's the case, and you want to find the mass of vitamin C needed to decolourise 1mL of 1% DCPIP, then times 10mg by the volume of juice used.

    For example, if it takes 5 mL of juice to decolourise the DCPIP, and there's 10mg of vit C per 1mL of juice, then it's 50mg of vit C.
Submit reply
Turn on thread page Beta
Updated: November 10, 2008

University open days

  1. University of Edinburgh
    All Departments Undergraduate
    Sat, 22 Sep '18
  2. University of Exeter
    Undergraduate Open Days - Penryn Campus Undergraduate
    Sat, 22 Sep '18
  3. Loughborough University
    General Open Day Undergraduate
    Sat, 22 Sep '18
Which accompaniment is best?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.