# Further trigonometry- compound identities.

#1
For the most part this question makes sense. I’m just not quite certain on when it asks the max and smallest value.

Question 6.
So, writing as a single trig function is straightforward

Given the compound identity, use its identity.

So, first part for:
a.sin(x+π/4)

If I take this answer and imagine
on the sin x graph, it’s max x value must be π/4. I’m not sure if I’m understanding the question correctly
0
1 week ago
#2
(Original post by KingRich)
For the most part this question makes sense. I’m just not quite certain on when it asks the max and smallest value.

Question 6.
So, writing as a single trig function is straightforward

Given the compound identity, use its identity.

So, first part for:
a.sin(x+π/4)

If I take this answer and imagine
on the sin x graph, it’s max x value must be π/4. I’m not sure if I’m understanding the question correctly
It would help to see the question.
But if a is positive, youre correct that the first max value would be at x=pi/4.
0
#3
(Original post by mqb2766)
It would help to see the question.
But if a is positive, youre correct that the first max value would be at x=pi/4.
Oops forgot to attach.

0
1 week ago
#4
(Original post by KingRich)
Oops forgot to attach.

So looks like youre good?
0
#5
(Original post by mqb2766)
So looks like youre good?
I believe I’m applying the transformation based on the single trigonometric value that I find?
Hence, x moves left by 45degress which is the reason for the new max value being at 45 degrees. For the smallest possible value of x is what I’m not sure about?
0
#6
(Original post by mqb2766)
So looks like youre good?
Lol. What am I saying right now. Max value is as I said and the x=π/4 and y=1. What the heck man.
Last edited by KingRich; 1 week ago
0
1 week ago
#7
(Original post by KingRich)
Lol. What am I saying right now. Max value is as I said and the x=π/4 and y=1. What the heck man.
Agreed. You can think of it as transformations, but the easiest thing will be simply the sub the "obvious" value in to get sin(pi/2).
0
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