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need help with this physics ideal gases question!!
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anonymous12345.
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#1
Issac physics G2.1
What is the volume of a mole of gas at atmospheric pressure (1.01*10^5 Pa) and at 20 ∘C? Give your answer to two significant figures.
What is the volume of a mole of gas at atmospheric pressure (1.01*10^5 Pa) and at 20 ∘C? Give your answer to two significant figures.
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Luwei
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devnp1
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Meli5
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pV = nRT
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
Last edited by Meli5; 1 month ago
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anonymous12345.
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#5
(Original post by Meli5)
pV = nRT
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
pV = nRT
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
i didnt change into kelvin
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zasng45
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#6
(Original post by anonymous12345.)
Issac physics G2.1
What is the volume of a mole of gas at atmospheric pressure (1.01*10^5 Pa) and at 20 ∘C? Give your answer to two significant figures.
Issac physics G2.1
What is the volume of a mole of gas at atmospheric pressure (1.01*10^5 Pa) and at 20 ∘C? Give your answer to two significant figures.
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Meli5
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anonymous12345.
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now how do you upvote the answer lmaoo
(Original post by Meli5)
pV = nRT
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
pV = nRT
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
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Meli5
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#9
(Original post by anonymous12345.)
now how do you upvote the answer lmaoo
now how do you upvote the answer lmaoo
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