# Intergral sub

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#1
struggling to show the (1+t^-2)/2 part, I've tried showing it directly and also tried showing it from the RHS but can't seem to factorise into anything useful
Last edited by Student 999; 1 month ago
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1 month ago
#2
(Original post by Student 999)
struggling to show the (1+t^-2)/2 part, I've tried showing it directly and also tried showing it from the RHS but can't seem to factorise into anything useful
I’d say let the x^2+1=t instead of the full thing, if you want me to follow that through to see if i get anywhere let me know.
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#3
(Original post by RandomE)
I’d say let the x^2+1=t instead of the full thing, if you want me to follow that through to see if i get anywhere let me know.
Don't think that'll work since you want the f(t) group aswell
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#4

I've managed to show it now but would there have been a shorter way about it?
Last edited by Student 999; 1 month ago
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#5
For the second part I could directly just do my substitution from part a and get the answer, what I did is referenced part a to save time but my explanation on how they're linked feels mathematically weak?
Last edited by Student 999; 1 month ago
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1 month ago
#6
Don’t reckon so
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1 month ago
#7
(Original post by Student 999)
For the second part I could directly just do my substitution from part a and get the answer, what I did is referenced part a to save time but my explanation on how they're linked feels mathematically weak?
Id guess that would be the solution they're expecting. Not sure why you think its weak.
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#8
(Original post by mqb2766)
Id guess that would be the solution they're expecting. Not sure why you think its weak.
I meant as in the why I can directly use f(t)= t^-3, would I not need to give some form of explanation?
Last edited by Student 999; 1 month ago
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1 month ago
#9
(Original post by Student 999)
I meant as in the why I can directly use f(t)= t^-3, would I not need to give some form of explanation?
Thats the form of the function in the original integral, so youre simply applying the general result from part a) to a particular function.
Last edited by mqb2766; 1 month ago
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