URGENT as maths help needed

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_martha
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#1
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#1
Does anyone know how to answer this?

Show that 1/cosθ + tanθ = cosθ/1-sinθ

I have got as far as changing tanθ into sinθ/cosθ but not sure what to do from here.
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Skiwi
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If you've changed tan(theta) into sin/cos then you should see that the left hand side can be added together due to the common denominator.

Now you need to figure out how to change it into the correct form,
if you notice the cos on the bottom moves to the top, which to me would suggest you can make the top have a cos^2 in it. you could use the fact that cos^2+sin^2=1 and multiply both top and bottom by the same thing to get the cos^2 you want.
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Natsudragon
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(Original post by _martha)
Does anyone know how to answer this?

Show that 1/cosθ + tanθ = cosθ/1-sinθ

I have got as far as changing tanθ into sinθ/cosθ but not sure what to do from here.
ok so it is 1+sinΘ/cos Θ on the left.. multiply numerator and denominator with 1-sinΘ .. ull get cos2Θ/cos Θ(1-sinΘ) ... common factors remove .. then ull get the right hand side yea
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Skiwi
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(Original post by Natsudragon)
ok so it is 1+sinΘ/cos Θ on the left.. multiply numerator and denominator with 1-sinΘ .. ull get cos2Θ/cos Θ(1-sinΘ) ... common factors remove .. then ull get the right hand side yea
It's best to give the op hints and let them figure it out rather than telling them how to do it from the get go.
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Natsudragon
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(Original post by Skiwi)
It's best to give the op hints and let them figure it out rather than telling them how to do it from the get go.
ohhh yeaaa .. ill do that next time .. thnx
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_martha
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(Original post by Natsudragon)
ok so it is 1+sinΘ/cos Θ on the left.. multiply numerator and denominator with 1-sinΘ .. ull get cos2Θ/cos Θ(1-sinΘ) ... common factors remove .. then ull get the right hand side yea
thank youuu
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Natsudragon
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#7
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Heheee
(Original post by _martha)
thank youuu
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