# Mechanics question - collisions

Announcements
#1
Please can someone explain why in part b, it is root(2)/2 as the coefficient for the unit vector for the line of centres?
Thank you.
Last edited by Rhys_M; 1 month ago
0
1 month ago
#2
assuming the numbers are right, so
c = i-j
then to get the unit magnitude, you divide by |c|, so
c/|c| = 1/sqrt(2) (i - j)
or rationalizing the denominator
sqrt(2)/2 (i - j)

By construction, the magnitude of this new vector is 1.
Last edited by mqb2766; 1 month ago
0
#3
(Original post by mqb2766)
assuming the numbers are right, so
c = i-j
then to get the unit magnitude, you divide by |c|, so
c/|c| = 1/sqrt(2) (i - j)
or rationalizing the denominator
sqrt(2)/2 (i - j)

By construction, the magnitude of this new vector is 1.
Oh shoot of course it's the same as 1/root2 isn't it lol - thank you
0
X

new posts
Back
to top
Latest

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### Poll

Join the discussion

#### Do you know what you'll do if you don't get the grades you're hoping for?

Find something else in clearing (8)
33.33%
Take a gap year (5)
20.83%
Resit my exams (6)
25%
Look for alternate pathways to the career I want (3)
12.5%
I don't know yet (1)
4.17%
Something else (tell us in the thread) (1)
4.17%