Physics stationary waves help
Watch this thread
Announcements
Page 1 of 1
Skip to page:
melonlord.xx
Badges:
12
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#1
If someone could help me with this question that would be great (:
"In a resonance tube experiment, the shortest length of tube to give a loud sound is found for two different tuning forks. For a fork of a frequency 256Hz, the length is 32cm and for a fork of frequency 512Hz, the length is 15.4cm. Calculate the speed of sound in the tube and the distance of the antinode above the top of the tube."
Thanks
"In a resonance tube experiment, the shortest length of tube to give a loud sound is found for two different tuning forks. For a fork of a frequency 256Hz, the length is 32cm and for a fork of frequency 512Hz, the length is 15.4cm. Calculate the speed of sound in the tube and the distance of the antinode above the top of the tube."
Thanks

0
reply
Stonebridge
Badges:
13
Rep:
?
You'll earn badges for being active around the site. Rep gems come when your posts are rated by other community members.
#2
Report
#2
(Original post by melonlord.xx)
If someone could help me with this question that would be great (:
"In a resonance tube experiment, the shortest length of tube to give a loud sound is found for two different tuning forks. For a fork of a frequency 256Hz, the length is 32cm and for a fork of frequency 512Hz, the length is 15.4cm. Calculate the speed of sound in the tube and the distance of the antinode above the top of the tube."
Thanks
If someone could help me with this question that would be great (:
"In a resonance tube experiment, the shortest length of tube to give a loud sound is found for two different tuning forks. For a fork of a frequency 256Hz, the length is 32cm and for a fork of frequency 512Hz, the length is 15.4cm. Calculate the speed of sound in the tube and the distance of the antinode above the top of the tube."
Thanks

However...
To give you a couple of clues:
For a resonance tube at it's lowest (fundamental) frequency, the wave inside is a quarter of the wavelength of the sound wave.
Speed of sound = frequency x wavelength.
However, there is what is called an 'end correction' to the tube, because the quarter wave doesn't fit exactly inside and pokes out a bit. This 'bit' is the end correction.
Have you done this in your theory?
You get rid of the error caused by the end correction by making the 2 different measurements, as given in the question.
Does this help?
Last edited by Stonebridge; 1 month ago
0
reply
X
Page 1 of 1
Skip to page:
Quick Reply
Back
to top
to top