M1 mechanics resolving forces

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Goldenknight
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#1
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My question is regarding how we do this

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The answer sheet shows that I have to use cosine rule and draw a triangle to find this even tho the question does not specify a method.

The method I know is finding the x-components and y-components for each forces shown in the question and using pythagorus theorem to get the magnitude. Then using Tan theta =y/x to find the angle
I tried doing that and got the same answer as in the answer sheet

Do I really have to do the method shown in the answer sheet? Or is it an alternative option. I would not prefer if I lose marks for using the method I know so would like to know this. The textbook does not specify anything either regarding this

I am doing the exam privately btw so I cant really ask any teacher as I am self studying

Examboard is Edexcel A level Mechanics
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Jpw1097
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#2
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#2
(Original post by Goldenknight)
Name:  1.PNG
Views: 14
Size:  266.4 KB

My question is regarding how we do this

Name:  2.PNG
Views: 13
Size:  380.6 KB

The answer sheet shows that I have to use cosine rule and draw a triangle to find this even tho the question does not specify a method.

The method I know is finding the x-components and y-components for each forces shown in the question and using pythagorus theorem to get the magnitude. Then using Tan x =Sin/Cos to find the angle

Do I really have to do the method shown in the answer sheet? Or is it an alternative option. I would not prefer if I lose marks for using the method I know so would like to know this

I am doing the exam privately btw so I cant really ask any teacher as I am self studying

Examboard is Edexcel A level Mechanics
Yes, you can find the x and y components and then just construct a right angled triangle.

You will never lose marks if you get the right answer using a valid method.
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Goldenknight
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#3
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#3
(Original post by Jpw1097)
Yes, you can find the x and y components and then just construct a right angled triangle.

You will never lose marks if you get the right answer using a valid method.
Ahh okay thats great to know. Thanks!
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