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# !An Advanced Algebraic question! watch

1. Hi guys,

I am stuck on a question in my text book. It says "show that each algebraic fraction simplifies to the given expression." Here goes...

2/x+1 + 5/x+2 =3 simplifies to 3x^3 +2x-3=0

Basically I can solve these equations when the brackets are the numerators, but somehow I cannot solve them when the denominators need to be put into brackets (etc)

Help

2. Is that the question?
3. (Original post by jayshah31)

Is that the question?

No it does not equal 0. It equals 3
4. find the comon denominator and then you should be able to show that it is equal to 3x^3 +2x-3=0... but dont forget to include the 3 in ur calculations
5. (Original post by Sophie Maywood)
No it does not equal 0. It equals 3
Ah. I see you've edited your original post Do the above, i.e. multiple everything by

You can see you can cancel the fractions down and then expand those brackets, bring everything on one side (so it = 0), and you should be done :0
Jay
6. I have crossed multiplyed and so far I have got 2(x+1)+5(x+1). Although how do you include the 3 in the calculation?
7. (Original post by Sophie Maywood)
I have crossed multiplyed and so far I have got 2(x+1)+5(x+1). Although how do you include the 3 in the calculation?
The first one should be . I edited my above post earlier, does that help now?
8. (Original post by Sophie Maywood)
I have crossed multiplyed and so far I have got 2(x+1)+5(x+1). Although how do you include the 3 in the calculation?
the comon denominator would be (x+1)(x+2)

so if you subtract both sides by 3 teh u will get something like this :

2(x+2)+5(x+1) -3(x+1)(x+2)
(x+1)(x+2)

but somehow i cant get to ur answer... are u sure that u typed in the right solution?
9. Here

Spoiler:
Show

Might have typed it out wrong, but it works on paper.
10. giving full solutions is not ideal lol
11. (Original post by neomilan)
giving full solutions is not ideal lol
Hence the spoiler

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