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Idk131
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#1
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#1
How does log2 (little 2) x= +_3 give x=1/8 as a solution??
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Idk131
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#2
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#2
(Original post by Idk131)
How does log2 (little 2) x= +_3 give x=1/8 as a solution??
I though you couldn't have a negative log but the answer gives the -3 solution not the positive one?
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Idk131
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#3
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#3
Anyone? I am really stuck on this and am not sure how logs even work now tbh, is there another formula/rule that I should be made aware of? I though the solution would be x=9 not 1/8
Last edited by Idk131; 1 month ago
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T!gger34
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#4
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#4
Logs are indices.

In base 2 logs, log8= 3, since 2^3=8
In base 10 logs, log100= 2, since 10^2=100

Try to remember either of those two facts as a starting point of comprehension.

Can you post an actual piccie of the question, since something may have been lost in translation, as it were.
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davros
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#5
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#5
(Original post by Idk131)
I though you couldn't have a negative log but the answer gives the -3 solution not the positive one?
A logarithm can be negative, but you can't take the log of a negative (at least, not at A level)
log_2{x} = a means 2^a = x, so have a think about what log_2{x} = -3 is telling you
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Archock
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#6
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#6
(Original post by Idk131)
How does log2 (little 2) x= +_3 give x=1/8 as a solution??
2^-3=x

or 1/2^3=x

or 1/8=x

That's it.
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Idk131
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#7
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#7
Ah ok thank you so much guys!
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toxicgamage56
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#8
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#8
eh, why are we ignoring the 2^3 = 8 solution?
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T!gger34
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#9
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#9
(Original post by toxicgamage56)
eh, why are we ignoring the 2^3 = 8 solution?
The op hasn't posted the actual question. There may have been a detail in it which explained why?
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