The Student Room Group

Geometry

One of my weakest topics, for the final part is my diagram correct?
I used the fact that the angle ACB is trisected to tests if my diagram was at least drawn correctly but the angles of triangle FHC doesn't add up to 180 so can't be rightIMG_1D38FC6896FC-1.jpegScreenshot 2022-07-01 at 15.20.39.png
(edited 1 year ago)
I just picked a common angle for alpha=30 and x=1 to draw a representative diagram.
So you end up drawing a 30-60-90 triangle, the hypotenuse AB is 2, then its 1:sqrt(3):2, so its in a semicircle (Thales, C is on the circumference) of radius 1 with AB being the base, D being the center, E bisecting DB and F sitting on D and that seems to work.
(edited 1 year ago)

Quick Reply

Latest