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    • Thread Starter

    I'm really stuck on this question, I don't know whether it's because it has an unknown or what..but I don't really know where to start.
    The question is:

    The straight line passing through point P(2,1) and the point Q(k,11) has gradient -\frac{5}{12}.
    a) Find the equation of the line in terms of x and y only.
    b) Determine the value of k.

    I have no idea where to start so a step by step explanation, or anything at all infact, would be very much appreciated. Thanks

    You know it is in the form y = mx + b.

    y - y1 = m(x - x1).

    You know m as it is a straight line. (given points).

    Sub in 11 to find k.

    you have been given a point on a given line, as well as its gradient...which is what you need to construct an equation

    try using y-(b) = m(x -a)
    where a=2, b=1 and m=-5/12

    simplify and this gives the equation

    then use the co-ordinates for Q
    ie. substitute in y=11 and then solve to find k

    Hope that helps!

    ...someone got there before me
    • Thread Starter

    Thanks guys :]] God, I am truly hopless at maths! >.<
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