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# Logs Help watch

1. Solve for x :

I then get :

Dunno where to go from here though?
2. Multiply out and rearrange, the log bit just represents a number. i.e.
3. Try

Expand and get the x terms on one side, constants on the other.

That help at all?
4. (Original post by Sephrenia)
Try

Expand and get the x terms on one side, constants on the other.

That help at all?
I understand that, but i really don't know where to go from there to get x.
5. (Original post by Inertia)
I understand that, but i really don't know where to go from there to get x.
Expand the brackets. What do you get then?
6. Think of log3 / log 2 representing a number, you could call it a, then you'd have x - 1 = ax + a, then you can get all the x's on one side
7. (Original post by benwellsday)
Think of log3 / log 2 representing a number, you could call it a, then you'd have x - 1 = ax + a, then you can get all the x's on one side
Yes ok, but then surely it is x-ax=1 + a

which is x-x=1+a/a which gives 0 on the left hand side?
8. (Original post by Inertia)
Yes ok, but then surely it is x-ax=1 + a

which is x-x=1+a/a which gives 0 on the left hand side?
No. You divided by a, but only divided 2 terms by a. Once you have your brackets expanded you can take x out of one side. So you will have x(****)=1+a.
9. Inertia,

I am going to post the full solution as I think you are struggling to get to grips with this. Hope that is OK in this case.

Spoiler:
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