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    It's to do with rearranging algebraic fractions..I'm finding this particular one difficult at the moment..
    Would some kind soul please help me, and explain how to do it?
    My revision guide isn't really helping matters.

    Really sorry but I can't use that maths symbol TSR thing either :| So if someone could re-express this problem with the symbols that would be appreciated also so that it makes more sense!

    2x/5 - 4x+5/3 = x+8

    lmao I realise how retarded that probably looks! :P
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    (Original post by Jizzabelle)
    2x/5 - 4x+5/3 = x+8
    \frac{2x}{5}-\frac{4x+5}{3}=x+8

    Is that what you mean?

    LaTeX is easy by the way. Just quote me to see what I did.

    As for the question. I would multiply both sides of the equation by the lowest common mupltiple of 3 and 5 for a start and I'll point out that \frac{2x}{5}\times 15 \neq \frac{30x}{75}
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    First get rid of the annoying denominators by first multiplying the equation through by 5, and then multiplying it through by 3.
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    Thanks for your help guys, but I still don't get it . On first glance, I thought I had to..
    (Original post by Kolya)
    First get rid of the annoying denominators by first multiplying the equation through by 5, and then multiplying it through by 3.
    but, it didn't work out .

    2x - 4x+ 5 = 15x +120 ?
    = -2x + 5 = 15x + 120 ?
    moved the + 5 across
    - 2x = 15x + 115
    moved the 15x across..
    -17x=115

    I've really messed it up and I'm so confuuuused.
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    Your first line is wrong. Multiplying through by 5 gives 2x - \frac{20x + 25}{3} = 5x + 40, and then multiplying through by 3 gives 6x - 20x - 25 = 15x + 120 (I think!)
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    (Original post by Kolya)
    Your first line is wrong. Multiplying through by 5 gives 2x - \frac{20x + 25}{3} = 5x + 40, and then multiplying through by 3 gives 6x - 20x - 25 = 15x + 120 (I think!)
    Aye, I tried that way aswell, but it doesn't seem to work either :\
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    It does. Try again.
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    -14x-25=15x+120
    -145=29x
 
 
 
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