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    Wow heads hurting me and can't get around to get

    \frac{1}{5}(4-ln5)

    from

    -\frac{1}{5} (ln5+1) + (ln1+1)

    i thought it'd be like

    1/5(ln5+1) and ln1 = 0 so u'd just add 1 to get

    -\frac{1}{5}(ln5+2)
    then that to
    \frac{1}{5}(2-ln5)
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    Whats -1/5 + 1
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    So you have:

    \frac{-1}{5}(\ln 5 + 1) +1 = \frac{-1}{5}(\ln 5 + 1)+\frac{5}{5} = \frac{1}{5}(...)

    You can't just add a one to the inside of the brackets.
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    The above is all wrong by the way...
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    (Original post by Sophie Maywood)
    The above is all wrong by the way...
    If you are talking about the method the op was trying to do then you would be correct as has already been said in the post preceding yours.

    If you are talking about the method given by nottek then I think you will find it is correct.

    Either way, it is not very helpful to the op to simply say it is wrong. I think the fact that they are asking the question tells us that they know that they are not correct and so require some help.
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    (Original post by The Muon)
    If you are talking about the method the op was trying to do then you would be correct as has already been said in the post preceding yours.

    If you are talking about the method given by nottek then I think you will find it is correct.

    Either way, it is not very helpful to the op to simply say it is wrong. I think the fact that they are asking the question tells us that they know that they are not correct and so require some help.
    To the joke in your sig:

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    (Original post by Kevlar)

    -\frac{1}{5} (ln5+1) + (ln1+1)

    i thought it'd be like

    1/5(ln5+1) and ln1 = 0 so u'd just add 1 to get

    -\frac{1}{5}(ln5+2)
    This is the step where you've gone wrong, multiply out the bracket first then add the one.
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    (Original post by D-Day)
    To the joke in your sig:
    Lmao at the picture!
 
 
 
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