You are Here: Home >< Maths

# Quadratic Functions exam paper question watch

1. Given that the equation

kx^2 - 4x + k - 3 = 0

has equal roots, find the value of "k".

I know that a=k, b=-4, and c=k-3.

Then to put it into b^2 - 4ac I'd get:

(-4)^2 - 4 (k) (k-3) = 0
16 - 4k^2 + 12k = 0
[I can cancel down to:] 4 - k^2 + 3k = 0

2. k^2-3k-4 = 0 then solve it

(k-4)(k+1)

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: November 11, 2008
Today on TSR

### Edexcel C4 Maths Unofficial Markscheme

Find out how you've done here

### 1,863

students online now

Exam discussions

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams