A ball is thrown vertically upwards at 25m/s from a point P. Three seconds later a second ball B is also thrown vertically upwards from the point P at 25m/s. Taking the acceleration due to gravity to be 10m/s^2, calculate
i.) the time for which ball A has been in motion when the balls meet.
ii.) The height above P at which A and B meet.
I've done part one and got 4seconds (which i hope is right). need some hints on part 2 though.
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Need help with M1 question watch
- Thread Starter
- 11-11-2008 20:47
- 11-11-2008 21:46
you should have formed a simultaneous equation in s and t, and for part i) you solved for t, so now solve for s?