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    A ball is thrown vertically upwards at 25m/s from a point P. Three seconds later a second ball B is also thrown vertically upwards from the point P at 25m/s. Taking the acceleration due to gravity to be 10m/s^2, calculate

    i.) the time for which ball A has been in motion when the balls meet.
    ii.) The height above P at which A and B meet.

    I've done part one and got 4seconds (which i hope is right). need some hints on part 2 though.

    you should have formed a simultaneous equation in s and t, and for part i) you solved for t, so now solve for s?
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