The Student Room Group
Reply 1
well theres 52 cards in a pack and 12 face cards...

so 12/52 ?
Reply 2
oops misread the question :P

but surely then just multiply by 3?
Start by considering one pack of cards, there's usually 52 in these sorts of questions.
there are four suits, and 3 image cards in each suit. Consider the probability here.
then, multiply this by 3 as you have 3 packs. :smile:
Higgy90
well theres 52 cards in a pack and 12 face cards...

so 12/52 ?

sorry i didnt write up the whole question calculate the probability that he draws 1 image card, 2 image card and 3 image cards
Assume that there is an equal probability of choosing the cards. You are picking 3 cards from 156, 36 of which are image cards. The probability of having at least one image card in your chosen cards is 1 minus the probability of picking no image cards (these events partition the sample space).
The number of ways of picking 3 non image cards is (120x119x118)/6.
The number of ways of picking 3 cards from 156 is (156x155x154)/6
Therefore, the probability drawing an image card is

1 - (120x119x118)/(156x155x154)

Latest