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Probability of drawing cards watch

1. Hey I have a problem. The question which i cannot do is this:
A player chooses a card at random from each of 3 packs of cards.
Calculate the probability he draws an image card (king, queen or jack)
I have no idea how to even begin this question
2. well theres 52 cards in a pack and 12 face cards...

so 12/52 ?
3. i;ve seen you make a good few questions for probability and related questions in the past couple of days.

try and think a bit harder. what are the probabilities?

how many cards are there in a pack?
how many kings, queens and jacks are there in total in each pack?
so what is the probability of picking a jack/queen/king (picture card) from the pack?
what about the same questions but for 3 packs, if a player draws one, at random, from each?
4. oops misread the question :P

but surely then just multiply by 3?
5. Start by considering one pack of cards, there's usually 52 in these sorts of questions.
there are four suits, and 3 image cards in each suit. Consider the probability here.
then, multiply this by 3 as you have 3 packs.
6. are you sure? the question merely states, what is the chance of drawing a picture card, not specifically one. so all 3 could be picture cards, or just two, or just one...

Spoiler:
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the way i would do it is to say that:
7. (Original post by Higgy90)
well theres 52 cards in a pack and 12 face cards...

so 12/52 ?
sorry i didnt write up the whole question calculate the probability that he draws 1 image card, 2 image card and 3 image cards
8. Assume that there is an equal probability of choosing the cards. You are picking 3 cards from 156, 36 of which are image cards. The probability of having at least one image card in your chosen cards is 1 minus the probability of picking no image cards (these events partition the sample space).
The number of ways of picking 3 non image cards is (120x119x118)/6.
The number of ways of picking 3 cards from 156 is (156x155x154)/6
Therefore, the probability drawing an image card is

1 - (120x119x118)/(156x155x154)

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Updated: November 11, 2008
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