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    In the film, John Nash writes this problem on a board and says that for some it will take months to solve and for others, your whole life:

    Find a subset X of R^3 with:

    V={F:R^3\X --> R^3 so \nabla x F = 0}

    W={F=\nablag}

    dim(V/W)=8

    Well I've got no idea but maybe a TSRian may be able to solve it. I bet it's not as hard as he says it is.
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    i'm betting it's something John Nash gave himself when they interviewed him for the film :P
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    ... I think I saw this problem on a blackboard at the CMS. Hmmm...
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    Looks like the stuff we are doing at the moment lol
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    There must be a elegant solution

    According to the film the anwser is elegant.


    I'm pretty sure Nash didn't make that up. However, according to wikipedia John Nash was a really bad teacher and his exam is mean't to be really hard.
    Basically, his exams are a bunch of trick questions.
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    (Original post by Simplicity)
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    There must be a elegant solution

    According to the film the anwser is elegant.


    I'm pretty sure Nash didn't make that up. However, according to wikipedia John Nash was a really bad teacher and his exam is mean't to be really hard.
    Basically, his exams are a bunch of trick questions.
    Lets have some justification for any of the [Citation needed]. However, he did have a habit of setting unsolved problems in his exam where he thought (mistakenly) that he had an answer
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    A friend told me about a problem from the film, it might have been that one, and I think an answer was 1? I wouldn't have a clue how to find it though. What does dim mean? I've not come across that expression and google shows no results.
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    dim(V/W)=8
    I'm watching the film on youtube now, and I think thats not on the board.

    Dammit, in the film he said the solution is elegant, however I think he means theres a elegant way to do it.

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    The vector fields are not rational functions

    He said this in the film, when pointing out the mistake his student made trying to solve it.
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    (Original post by fisherman)
    A friend told me about a problem from the film, it might have been that one, and I think an answer was 1? I wouldn't have a clue how to find it though. What does dim mean? I've not come across that expression and google shows no results.
    Dimension.
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    You guys could be here for quite some time.

    W and V are quantities, aren't they?
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    V is a set of vector fields (i.e. vector-valued functions), and W is another set of vector fields. I'm pretty sure W is contained in V (since all conservative fields are irrotational), and so V/W is presumably some kind of quotient space...
 
 
 
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