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Velocity time graph

A moving train travels through station P with a speed of 20ms^1 and accelerate uniformly for 2s reaching a speed of 48ms^1. It continues with this speed for 5s and then ******s uniformly for another 3s and comes to rest at station Q. Find:
The distance from station P to Q
The average speed of the train
The acceleration
Acceleration is difference in speed divided by the time
I'm pretty sure the distance is the area under the velocity time graph if you drew it out
Original post by emmap2003
Acceleration is difference in speed divided by the time
I'm pretty sure the distance is the area under the velocity time graph if you drew it out

My problem is how to draw the graph
Original post by FGCMIN17309703
My problem is how to draw the graph

uniform acceleration looks like a straight line on a velocity time graph...
so for the first section you'd draw a point for 20 m/s at t=0s and a point for 48 m/s at t=2s and then connect them with a straight line.

more on velocity time graphs here https://www.bbc.co.uk/bitesize/guides/z2b9hv4/revision/5
(edited 1 year ago)
Thank you so very much
I am really grateful

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